two springs have their respective force constants k1 and k2 both are streached till their elastic potential energies are equalif the stretching forces 5ccwhwee -Physics - TopperLearning.com

Jun 06, 2019 Two springs have their respective force constants K1 and K2. Both are stretched till their elastic potential energies are equal. If the stretching forces are F1 and F2 find F1/ F2

First off, for this type of question, you need to remember the fact that the force from a spring comes from how long it is stretched multiplied by its constant, k1 or k2. In series, both of these springs would not stretch equally, as they have different spring constants. So, we can come up with 2 equations f1= k1*x1-(1) and f2=k2*x2-(2). Assuming a force F is applied on this system, the springs will stretch a combined

TCYonline Question & Answers: get answer of Two springs have their force constant as k1 and k2 (k1 > k2). When they are stretched by the same force, For full functionality of this site it

May 06, 2012 Two springs, with force constants k1 and k2 are connected in series, as shown in the figure. How much work is required to stretch this system a distance x from the equilibrium position? (Use any variable or symbol stated above as show more Two springs, with force constants k1 and k2 are connected in series, as shown in the figure.

Question: Two springs have spring constants k1 and k2 > k1. Connected as shown, they act like one spring Two springs have spring constants k1 and k2 > k1. Connected as shown, they act like one spring. A) Compute the spring constant of the combination. Express the answer in terms of the variables k1 and k2.

Feb 27, 2011 Equivalent spring constant.. Homework Statement This is a general doubt i have..when two springs of spring constants k1 and k2 are connected in series the equivalent k is given by 1/k=1/k1+1/k2 and when they are in parallel it is k=k1+k2..Now in these cases do we assume that the natural length of the springs are same? Homework Equations

Two springs have force constants k1 and k2(k1 k2) On which spring is more work done,if(i)they are stretched by the same force (ii) they are stretched by the same amount - Physics -

two springs have force constants k1 and k2 where k1 k2 on which spring more work is done if they are stretched by the same magnitude of force - Physics - TopperLearning.com

Two springs, with force constants k1=175N/m and k2=270N/m, are connected in series When a mass m=0.50kg is attached to the springs, what is the amount of stretch, x? asked by ana on March 27, 2017

TCYonline Question & Answers: get answer of Two springs have their force constant as k1 and k2 (k1 > k2). When they are stretched by the same force, For full functionality of this site it

Two springs of force constants k and 2k are connected to a mass as shown in figure. a body having mass m is attached with two springs having spring constants k1 and k2. asked Apr 25 in Physics by Ankitk (73.9k points) A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students

May 06, 2012 Two springs, with force constants k1 and k2 are connected in series, as shown in the figure. How much work is required to stretch this system a distance x from the equilibrium position? (Use any variable or symbol stated above as show more Two springs, with force constants k1 and k2 are connected in series, as shown in the figure.

Question: Two springs have spring constants k1 and k2 > k1. Connected as shown, they act like one spring Two springs have spring constants k1 and k2 > k1. Connected as shown, they act like one spring. A) Compute the spring constant of the combination. Express the

Jan 08, 2017 A 3.00-kg block is connected to two ideal horizontal springs having force constants k1 = 25.0 N/cm and k2 = 20.0 N/cm The system is initially in equilibrium on a horizontal, frictionless surface.

Apr 15, 2010 When the two springs of spring constant k1 and k2 are connected in series, they behave like a single spring of equivalent spring constant k = k1*k2/(k1+k2).

Answer to: If two springs have their spring constants as k1 and k2 (k1>k2 . When they are stretched by same force what will be the relation between

Two springs have force constants k1 and k2(k1 k2) On which spring is more work done,if(i)they are stretched by the same force (ii) they are stretched by the same amount - Physics -

Two springs, with force constants k1=175N/m and k2=270N/m, are connected in series When a mass m=0.50kg is attached to the springs, what is the amount of stretch, x? asked by ana on March 27, 2017

Mar 23, 2018 Two springs, of force constants k 1 and k 2 are connected to a mass m as shown. The frequency of oscillation of the mass is f. If both k 1 and k 2 are made four times their original values, the frequency of oscillation becomes (a) 2f (b) f/2 (c) f/4 (d) 4f.

Force constants k1 and k2 of two springs are in the ratio 5:4 .They are stretched by same length .If potential energy stored in one spring is 25 J then potential energy stored in second spring is

Correct answer to the question: Two springs have force constants k1 and k2. on spring work done is more if 1) are streched by the same force and - brainsanswers.in

Sep 24, 2019 Two springs, with force constants k1=170N/m and k2=255N/m, are connected in series, as shown in (Figure 1).? When a mass m=0.75kg is attached to the springs, what is the amount of stretch, x? Express your answer to two significant figures and include appropriate units.

Dec 19, 2011 Two springs of constants k1 and k2 are connected in series to a block a that vibrates in simple harmonic motion with a period of 5 s. When the same

Two springs with constants k1 and k2 are in a series Using the fact that force balance must apply everywhere, what is the equivalent spring constant of a single spring? That is, if you had to swap out a single spring for the two springs that are in series, what would its spring constant need to be to generate the same force at any displacement?

Nov 06, 2011 Here's the trick: when you hang springs in a series like this, they have the same force applied across each spring, so F1 = F2 = F. F1*k1 + F2*k2 = F*k1 + F*k2 = F*(k1 + k2) F*(k1 + k2) = Dtotal. F*Ktotal = Dtotal. Ktotal = k1 + k2. So Ktotal is just the sum of k1 and k2.

Answer to: Two springs have force constant K1&K2 (K1 greater than K2) . Each spring is extended by the same force F. If their elastic potential

Feb 04, 2018 Mass * Acceleration due to gravity = (k1+k2) * dx/dt. Where x is the distance the mass is moved to due to the weight of the mass m ; ) →m*9.81 * dt = (k1+k2) dx. Integrating On both sides and assuming the initial conditions to be zero, →m*9.81*t =

Nov 30, 2013 1) A 3.00-kg block is connected to two ideal horizontal springs having force constants k1 = 25.0 N/cm and k2 = 20.0 N/cm (the block is at the middle of two springs). The system is initially in

Two springs with spring constants K1=1500 N/m and K2=3000 N/m are stretched by the same force. Two springs with spring constants K1=1500 N/m and K2=3000 N/m are stretched by the same force. The ratio of potential energy stored in spring will be 18000+ students are using NEETLab to improve their score. What about you? Solve Previous Year

Two springs of force constants k1, and k2, are connected in series. The spring constant of the combination is (A) k1+k2 (B) (k1+k2/2) (C) (k1+k2/k1 k2) (D) (k1k2/k1+ k2). Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities $\omega_1$ and

Two springs, of force constants k1 and k2, are connected to a mass m as shown. The frequency of oscillation of the mass is f. If both k1 and k2 are made four times their original values, the frequency of oscillation becomes from Physics Oscillations Class 11 Mizoram Board

Sep 13, 2011 For two springs in parallel the net force is equal to the sum of the force of each spring. Let one spring have spring constant k1 and the second k2 . Feq = keqx = (k1+k2)x keq = k1+k2 For two

two springs have force constant K1 and K2 (k1k2) EACH SPRING IS EXTENDED BY SAME FORCE f , IF THEIR elastic potential energy are E1 and E2 then, E1/E2 IS = - Physics -

They have spring constants 2k and k respectively.The springs are stretched, separately, by a force that is gradually increased from zero up to a certain maximum value, the same for each . asked by Taylor on October 28, 2014; physics. A single mass (m1 = 3.1 kg) hangs from a spring in a motionless elevator. The spring constant is k = 338 N/m.

Two springs have their force constants k1 and k2 (K2>K1). When they are stretched by the same force, work done is 1) Same in both the springs 2) More in spring K1 3) More in spring K2 4) None 4. A lorry and a car moving with same KE are brought to rest by applying the same retarding force.

two springs are identical except for their spring constants k2 > k1. If the same force is used to stretch the springs,

Mar 29, 2017 2 springs,with force constants k1=125N/m and k2=275N/m are connected.Mass=0.95kg is attached to the springs,what is the amount of stretch,x?

You have four springs that have a 20 lbf/in (pounds of force per inch) rate. To calculate the spring rate in parallel you must add up the spring rates of all the springs as shown in the formula below. Keq = k1 + k2 + k3 + k4. Keq = Equivalent Rate; k1 = Rate 1; k2 = Rate 2;

Oct 19, 2012 For springs in series, the Force is the same but the X is additive. K1 =1.16 Nmm K2 = 2.99 N/mm Ke =Equivalent. Stiffness. X = X1 + X2 Ke = F/X X= F/Ke X1 = F/K1 X2 = F/ K2. F/Ke = F/K1 + F/K2. 1/Ke = 1/K1 + 1/ K2. Ke = K1 K2 /(k1 + K2) = (1.16x2.99)/(1.16 + 2.99) =

Two springs have spring constants k1 and k2 > k1. Connected as shown in (Figure 1) , they act like one spring. 1.) Compute the spring constant of the combination.

two springs have force constants k 1 and k 2. Both are stretched till their elastic energies are equal .If the stretching forces are F 1 and F 2 then F 1 : F 2 is See Attachment

Consider two massless springs connected in parallel. Springs 1 and 2 have spring constants k1 and k2 and are connected via a thin, vertical rod. A constant force of magnitude F is being exerted on the rod. The rod remains perpendicular to the direction of the applied force so that the springs are extended by the same amount.

question_answer1) Two bodies M and N of equal masses are suspended from two separate massless springs of force constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude M to that of N is [IIT-JEE 1988; MP PET 1997, 2001; MP PMT 1997; BHU 1998; Pb.

Solution Two springs of force constants K1 and K2 (K1> K2) are stretched by same force. If W1 and W2 be the work done stretching the springs then Concept: Elastic Energy.

Two springs of constants k1 and k2 have equal highest velocities - 12204442 p 30 periodic table of elements and report Two solid spherical planets of equal radii R having masses 4 M and 9 M their centre are separated by a distance 6 R. A projectile of mass m is sent fr mass 4 M towards the havier planet. what is the distance r of the

For two springs in parallel the net force is equal to the sum of the force of each spring. Let one spring have spring constant k1 and the second k2 . Feq = keqx = (k1+k2)x keq = k1+k2 For two

(.550)(9.8)/(. 063)=85.6 N/m Explain why kx=mg F = -mg = - kx, where x is the displacement from the natural equilibrium length of the vertical spring Explain why the k value for the two springs in parallel system is equals to k1+k2. With two springs in parallel, pushing down with the same displacement gives you twice the force pushing back.

Two light springs of force constants k1 and k2 each 3.2 Nm-1 and a block of mass 200g are in one line AB on a smooth horizontal table such that one end of the each spring is fixed on a rigid support and the other end is free as shown fig. The distance CD between the free ends of a spring is 60cm.

Two springs in series Consider two massless springs connected in series. Spring 1 has a spring constant , and spring 2 has a spring constant . A constant force of magnitude is being applied to the right. When the two springs are connected in this way, they form a system equivalent to a

Mar 29, 2017 2 springs,with force constants k1=125N/m and k2=275N/m are connected.Mass=0.95kg is attached to the springs,what is the amount of stretch,x?

Jul 23, 2011 A mass m slides on a frictionless horizontal surface, connected to two springs. If the springs have force constants k1 and k2. Show that the simple harmonic motion has period: T = 2pi * sqrt {m [(k1+k2)/(k1*k2)]} I can't seem to figure it out, please help!

Springs in Parallel Two springs are said to be in parallel when used as in the figure below. The two springs behave like on spring whose constant k is given by k = k1 + k2 Problem 3 What is the magnitude of the force required to stretch two springs of constants k1 = 100 N / m and k2 = 200 N / m by 6 cm if they are in parallel? Solution

Aug 22, 2014 Two springs have their force constant as K1 and K2 (K1 > K2). When they are stretched by the same force : A) no work is done in case of both the springs B) equal work is done in case of both the springs C) more work is done in case of second spring D) more work is done in case of first spring 18.

Dec 02, 2018 Two masses (M1 and M2) are connected together by 3 springs. The spring constants are k1, k2, k3. Block 1 is at equilibrium at x=0. Block 2 is at equilibrium at x=1. Determine a function for the force on the blocks. 2. Homework Equations 3. The Attempt at a Solution Without using the initial values, I was able to get the following equations

Oct 11, 2019 On release of masses, the half-springs experience restoring force and the masses move. With the result the mid-point of spring remains stationary and both half-spring-mass systems execute SHM, in opposite directions. Each sub-system, has initial PE =(1/4)kx^2. Spring constant of each half-spring = 2k. Initial compression is also shared equally = x/2.

Jun 26, 2018 Two springs are in a series combination and are attached to a block of mass 'm' which is in equilibrium. Spring constants:k and k’ Extensions:x and x’ respectively. Find the force exerted by spring

Dec 15, 2016 Parallel. When two massless springs following Hooke's Law, are connected via a thin, vertical rod as shown in the figure below, these are said to be connected in parallel. Spring 1 and 2 have spring constants k_1 and k_2 respectively. A constant force vecF is exerted on the rod so that remains perpendicular to the direction of the force. So that the springs are extended by the same amount.

If 2 springs of spring constants k1, k2 are connected in series, the equivalent spring constant would be k, defined by 1 / k = = 1 / k1 + 1 / k2 Thus 1 / k > 1 / k1 and 1 / k > 1 / k2; hence k < k1 and k < k2 Experiment 4(Parallel) Trial Weight (kg) Force(N) Spring Constant Displacement(m) 1.1 0.980 980N/m.001 2.15 1.47 294N/m.005 3.25 2.45 122.5N/m.020 4.35 3.43 98N/m.035 5.55 5.39 85.6N/m.063

Mar 29, 2017 2 springs,with force constants k1=125N/m and k2=275N/m are connected.Mass=0.95kg is attached to the springs,what is the amount of stretch,x?

Answer to: A block of mass m is connected to two springs of force constants k1 and k2. The block moves on a frictionless table after it is

We get F = x*(k1 + k2) = keq*x. The equivalent spring constant keq = k1 + k2. If two springs are connected in series, and a force F is applied, the force acts on both the springs changing the length of each differently. Let the spring constants of the springs be k1 and k2 and the change in length be x1 and x2.

Dec 19, 2011 Two springs of constants k1 and k2 are connected in series to a block a that vibrates in simple harmonic motion with a period of 5 s. When the same

Two springs have their force constant as k and k2(ki >k2). When they are stretched by the same force (a) No work is done in case of both the springs (b) Equal work is done in case of both the springs (c) More work is done in case of second spring (d) More work is done in case of first spring 4.A spring of force constant 10 Nm has an initial stretch 0.20 m.

Apr 01, 2007 Best Answer: The answer depends on whether the springs are connected in series or in parallel: (1) in series: (1/k total) = (1/k1) + (1/k2) (2) in parallel: k total = k1 + k2. Source(s):

Given that the force constants of the two springs are and , find the period of oscillation of the system. Answer: Let and represent the extensions of the first and second springs, respectively. Let and be the magnitudes of the forces exerted by the first and second springs, respectively.

Here, both the springs have a different constant or stiffness say k1 and k2. Thus, when one moves the mass by a displacement of x, one spring is pushed which pushes the other spring as well. Their combined displacement is x but we are yet to find their individual displacements.

Springs--Two Springs and a Mass. Consider a mass m with a spring on either end, each attached to a wall. Let and be the spring constants of the springs. A displacement of the mass by a distance x results in the first spring lengthening by a distance x (and pulling in the direction), while the second spring is compressed by a

Two springs are identical except for their force constants, k2>k1. If the same force is used to stretch the springs, compare the distance each spring will be stretched. When stretching, k1 will stretch a greater distance b/c it is easier to pull than k2.

You have two different springs that have the same unstretched length, but different spring constants k1 and k2. These springs can be hung vertically side-by-side (Figure A) or end-to-end (Figure B).

When two springs with spring constant or stiffness k1 & k2 are attached in series then the resultant spring constant K is equal to the sum of the reciprocal of the individual spring constant i.e 1/K =

Jul 25, 2018 (a) Two springs with spring constants k 1 and k 2 are connected in parallel, as shown in Fig. 4.18.What is the effective spring constant, k eff? In other words, if the mass is displaced by x, find the k eff for which the force equals F = -k eff x.

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